Monthly Archives: December 2024

For integer $n>0$, find the values of $$\sum\limits_{i=1}^{n}(-1)^{i+1}\cdot i\cdot\binom{n-1}{i-1}$$ Click here for the solution. Solution: If $n=1$, then \begin{flalign*} \sum\limits_{i=1}^{n}(-1)^{i+1}\cdot i\cdot\binom{n-1}{i-1} &= (-1)^{1+1}\cdot 1\cdot\binom{1-1}{1-1}& \\ &=1& \end{flalign*} If $n=2$, then \begin{flalign*} \sum\limits_{i=1}^{n}(-1)^{i+1}\cdot i\cdot\binom{n-1}{i-1} &=(-1)^{1+1}\cdot 1\cdot\binom{2-1}{1-1}+(-1)^{2+1}\cdot 2\cdot\binom{2-1}{2-1}& \\ &=1-2& \\ &=-1& … Continue reading →