-
Archives
- October 2025
- September 2025
- August 2025
- July 2025
- June 2025
- May 2025
- April 2025
- March 2025
- February 2025
- January 2025
- December 2024
- November 2024
- October 2024
- September 2024
- August 2024
- July 2024
- June 2024
- May 2024
- April 2024
- March 2024
- February 2024
- January 2024
- November 2023
- October 2023
- September 2023
- August 2023
- July 2023
- June 2023
- May 2023
- April 2023
- March 2023
- February 2023
- January 2023
- December 2022
- November 2022
- October 2022
- September 2022
- August 2022
- July 2022
- May 2022
- April 2022
- March 2022
- February 2022
- January 2022
- December 2021
- November 2021
- October 2021
- September 2021
- August 2021
- July 2021
- May 2021
- April 2021
- March 2021
- January 2021
- December 2020
- November 2020
- October 2020
- June 2020
- May 2020
- April 2020
- March 2020
- February 2020
- January 2020
- December 2019
- November 2019
- October 2019
-
Meta
Category Archives: Daily Problems
Solution to November 25, 2019′s Challenge
By connecting various points in the figure, we have the following: It is obvious that the radius of each quarter circle is $\dfrac{\sqrt{2}}{2}$, and the area of two green regions is: $$\dfrac{1}{2}-\dfrac{1}{4}\cdot\pi\cdot(\dfrac{\sqrt{2}}{2})^2=\dfrac{1}{2}-\dfrac{\pi}{8}$$ Therefore, the total area of the blue regions … Continue reading
Posted in Circles in a Square, Daily Problems, Geometry
Comments Off on Solution to November 25, 2019′s Challenge
Problem of the Day – November 25, 2019
In the following figures, 4 quarter circles join at the center of a unit square. Find the area of the shaded regions in blue.
Posted in Circles in a Square, Daily Problems, Geometry
Comments Off on Problem of the Day – November 25, 2019
Problem of the Day – November 24, 2019
In the following figure, a semi-circle is inscribed with maximum size inside a unit square. Find the radius of the the semi-circle.
Posted in Circles in a Square, Daily Problems, Geometry
Comments Off on Problem of the Day – November 24, 2019
Solution to November 23, 2019′s Challenge
According to Pythagoras theorem, the length of the street is $13$ blocks. However, if you look at the following diagram, Bob actually walks 16 street blocks 🙂
Posted in Daily Problems, Fun Math Facts, Geometry
Comments Off on Solution to November 23, 2019′s Challenge
Problem of the Day – November 23, 2019
Bob walks to school by walking up Geometry Street for 5 blocks, and turning 90 degrees to the right onto Square Street for 12 blocks. There is also a street that runs directly from Bob’s house to his school. If Bob … Continue reading
Posted in Daily Problems, Geometry
Comments Off on Problem of the Day – November 23, 2019