Author Archives: kevin

Hyperbolas Covered by a Quadrilateral

Four points $A$, $B$, $C$ and $D$ are chosen on each of $4$ hyperbola branches of $x^2y^2=1$ (as $y=\dfrac{1}{x}$ and $y=-\dfrac{1}{x}$ combined). Find the minimum area of the quadrilateral.🔑 Solution: Given that all 4 vertices of the quadrilaterial are on the $4$ branches, let … Continue reading

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HCS Summer School Exam 1 – 2025

Problem1: Let $x_{1}$ and $x_{2}$ be the root of $x^2-7x-9=0$. Find the value of $|x_{1}-x_{2}|$. Solution $$|x_{1}-x_{2}|=\dfrac{\sqrt{b^2-4ac}}{|a|}=\dfrac{\sqrt{(-7)^2-4\cdot(-9)}}{|1|}=\sqrt{85}$$ Problem 2: Find all solutions of $\sqrt{x+10}-\dfrac{6}{\sqrt{x+10}}=5$. Solution Let $y=\sqrt{x+10}$, we have $$y-\dfrac{6}{y}=5$$ Multiplying $y$ on both side of the equation, we have … Continue reading

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Hyperbolas Covered by a Triangle

$x^2y^2=1$ forms $4$ hyperbola branches, as $y=\dfrac{1}{x}$ and $y=-\dfrac{1}{x}$ combined. What is the smallest triangle in terms of area that it intersects all $4$ branches.🔑 Solution: Obviously, to be the smallest triangle, the vertices of the triangle must be on … Continue reading

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Geometry Challenge – 2025/06/07

Two opposite edges of a unit square are folded along one of the diagonal to form a parallelogram. Then, those two opposite edges on the parallelogram are folded together to form a trapezoid. Find the area of the trapezoid.🔑 Solution: … Continue reading

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Algebra Challenge – 2025/05/31

Let $P(x)$ is a polynomial with integer coefficients so that $P(d)=\dfrac{2025}{d}$, where $d$ is a positive divisor of $2025$. Find $P(x)$.🔑 Claim: There is no $P(x)$ to satisfy $P(d)=\dfrac{2025}{d}$, where $d$ is a positive divisor of $2025$. Lemma: If $P(x)$ … Continue reading

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